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Myrrh

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Myrrh
Okay, I've done the qiqirn part like 10 times now and I keep screwing up. I can't seem to find the little bastards with the given isolation options. <_< Is there some sort of easier way to find the bastards or do I just suck?
 
Okay, I've done the qiqirn part like 10 times now and I keep screwing up. I can't seem to find the little bastards with the given isolation options. <_< Is there some sort of easier way to find the bastards or do I just suck?

you just suck and its luck
 
Do in order:
Group searches:
1-4(Referred to from here out as "Group 1)
3-6(optional)
5-8("Group 2")
7-10(optional)
9-12("Group 3")

Pair searches:
use based off previous results:

You do not need to do pair searches for 1-2 or 11-12. Since these are a waste of pair searches. If you do not find all qiqirn in Group 1 searching 2-4, it's obviously #1.

Optional Group searches I listed are a good way of isolating qiqirn even further. If you come up with 2 in Group 1 and 2 in Group 2, but only 1 in the first optional search, if you find that qiqirn in your Group 1, you know that either of the Group 2 Qiqirn cannot possibly be #5 or #6, which just leaves you with #7 and #8.

Stretching Pair searches as much as possible is the key to winning it.
 
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Take a sheet of paper and note the clues. First by different groups of 4 then 2 etc. Also if you fail fake dc and you will be able to try again.
 
I thought it was really easy, but I love logic puzzles like that. I can try helping you later on if I'm on and you're still not past it. Skaw's method is most of what I was doing, though, so you should be able to get it from that. Occasionally you just run out of searches and it just comes down to luck; but I've been able to find out who they are with searches to spare.
 
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Another thing, that should've been obvious is if neither are suspicious, do not do an overlapping pair using either of the numbers involved.
 
Yeah, it's nice that they tell you if neither, one or both of the pair are suspicious.
 
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