POL NEWS : Mog Bonanza ??? a must do event !

Tomasello said:
Or take the 10 Mil, pay the gil sellers camping the V-Belt 3 Mil for the drop like some people do, and now you have a new V-Belt and 7 Mil in your pocket....
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Thus the Darth reference...
 
jamal said:
I'd assume it would be 1 winning number.

example: 12345 is the winning number from SE.

If your ticket was 12345 you'd win rank 1
If your ticket was 22345 you'd win rank 2
If your ticket was 23345 you'd win rank 3
If your ticket was 23445 you'd win rank 4
If your ticket was 23455 you'd win rank 5
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I think the bottom 4 would all leave you in rank 2, as you'd still have 4 numbers from the winning set, unless the order matters which i havn't heard, but could just have missed in the rules.

Either way sounds like fun, i'll definatly be playing.
 
shizzznit said:
100 million gil is pretty nice.. but.. if you think about it. What would you do after you got the gil? You can pretty much buy everything you could want from AH / LSes and well, for me thats a big loss of incentive to play the game, once theres nothing to work towards.

That being said, i want 100 mil ><
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With 100 mil you can always use that towards lvlling all jobs to 66 at least or even 75 if you're that ambitious and work on getting a Maat's cap, that's a goal to work on still. That or you can use the 100 mil to get Goldsmithing craft to 100?

There's still quite a lot you can do, 100 mil will just help you a lot more. You can even pimp out your favourite 75 job, fully merit them if they aren't fully merited, and solo a bunch of huge crap.
 
bladewind~ said:
I think the bottom 4 would all leave you in rank 2, as you'd still have 4 numbers from the winning set, unless the order matters which i havn't heard, but could just have missed in the rules.

Either way sounds like fun, i'll definatly be playing.
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I thought that too until I reread it:

The conditions for winning are as follows:
Rank 1 prize: all five digits.
Rank 2 prize: last four digits.
Rank 3 prize: last three digits.
Rank 4 prize: last two digits.
Rank 5 prize: last digit.

The way I interpret this, is even if you have the first four numbers correct, if you have the last number wrong, you don't win a thing.
 
jamal said:
I thought that too until I reread it:

The conditions for winning are as follows:
Rank 1 prize: all five digits.
Rank 2 prize: last four digits.
Rank 3 prize: last three digits.
Rank 4 prize: last two digits.
Rank 5 prize: last digit.

The way I interpret this, is even if you have the first four numbers correct, if you have the last number wrong, you don't win a thing.
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I can see what you mean now, my mistake. I would be incredibly annoyed to get the first 4 numbers correct and not win anything though, lol.
 
jamal said:
Rank 2 is interesting though, I'd take v-belt over 10M hands down (although Darth would disagree)
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it was only twice as much!

but generally i'd just be glad to hit tier 3 or 4

i could save that d. cloth for a v. cloak signed synth or something or sell it and get a signed hq stave, etc.
 
The last four digit reference might just be a bad translation, would not be the first time SE does that. Maybe the German or French version is more clear. Anyone read that?
 
100m i just get the relic weapons for all of my 75 jobs right away :)

well asap considering the mandatory waits.
 
Altheya said:
I think the term 'last four digits' is pretty clear in itself....
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I do believe he meant the term itself could be a mistranslation.
 
ok has anyone accually thoughtthis out.. more than likely its just gonna be a 5 randoms and the results of those randoms = the combination.

AND if that is the case the odds of winning rank 5 are 1,000,000,000,000,000 to 1 (1000*1000*1000*1000*1000) which honestly i dont think ANYONE is gonna win it.
 
sage sundi will have all the combonations and win by playing those numbers

that's how it'll work
 
Myrrh said:
Cept I doubt he knows about it.
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Wut?

20070707145352_12.jpg
 
Bleah nasty internet connections.

Had me d/c'ed so many times.

Anyway I would love it if the winning combo does not have to be the last 4/3/2/1.. so I went to look at the other POL announcements...

JP POL said:
当せん条件は、以下のとおりです。
1等：　5つの数字がすべて一致
2等：　下4けたの数字が一致
3等：　下3けたの数字が一致
4等：　下2けたの数字が一致
5等：　下1けたの数字が一致
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DE POL said:
Gewonnen hast du, wenn die festgelegte Zahl auf einem deiner Lose eine der folgenden Bedingungen erfüllt.
1. Gewinnklasse: Alle fünf Ziffern des Loses stimmen mit denen der Gewinnzahl überein.
2. Gewinnklasse: Die letzten vier Ziffern des Loses stimmen mit denen der Gewinnzahl überein.
3. Gewinnklasse: Die letzten drei Ziffern des Loses stimmen mit denen der Gewinnzahl überein.
4. Gewinnklasse: Die letzten zwei Ziffern des Loses stimmen mit denen der Gewinnzahl überein.
5. Gewinnklasse: Die letzte Ziffer des Loses stimmt mit der der Gewinnzahl überein.
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FR POL said:
Voici les conditions de gain :
- Gagnants du 1er rang : les 5 chiffres correspondent à la combinaison gagnante.
- Gagnants du 2e rang : les 4 derniers chiffres correspondent à ceux de la combinaison gagnante.
- Gagnants du 3e rang : les 3 derniers chiffres correspondent à ceux de la combinaison gagnante.
- Gagnants du 4e rang : les 2 derniers chiffres correspondent à ceux de la combinaison gagnante.
- Gagnants du 5e rang : le dernier chiffre correspond à celui de la combinaison gagnante.
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I don't understand French but the JP and DE POL doesn't sound encouraging.

Yups, I was really bored.

Bed time now...
 
Claudhert said:
ok has anyone accually thoughtthis out.. more than likely its just gonna be a 5 randoms and the results of those randoms = the combination.

AND if that is the case the odds of winning rank 5 are 1,000,000,000,000,000 to 1 (1000*1000*1000*1000*1000) which honestly i dont think ANYONE is gonna win it.
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If that were the case, then your possible results would not be from 0 to 99,999, but would be from 0 to 999,999,999,999,999. Your math's faulty.

A realistic possible implementation along your lines, would be 5 randoms of 0 through 9 and get the answer one digit at a time. But that would be 10*10*10*10*10 = 100,000, which is precisely the odds that we know it is anyway, so it's really just an overcomplicated way of getting to the same point.

There are 100,000 individual numbers between 0 and 99,999 inclusive. Precisely one of those numbers is the grand prize, therefore a single contest entry has 1 in 100,000 odds of winning the grand prize. You get into slightly (not significantly) more complicated statistics when you discuss your odds of winning with more than one contest entry, of course.

If you repeatedly pick the same number, the odds are unchanged. You don't have any more chances to win, but if you do win, you win bigger. (It seems that one can theoretically win a billion gil per character if the person buys 10 tickets with the same number, and those all turn out to be the winning number. However, the odds of the win are still 1 in 100,000.)

And if you pick a number guaranteed to be different than any of your previously picked numbers, then your chances in 100,000 increase by 1. Ten different numbers means a 10 in 100,000 (i.e. 1 in 10,000) chance of winning the grand prize.

Finally, if you pick several distinct numbers, but then get more than one ticket for at least one of those numbers, then you just apply the same logic as above. Ignore duplicates, and divide the number of unique numbers you have by 100,000, and there are your odds.

The math only really gets messy if you don't specify whether you're picking different or the same numbers. (All the above cases have later numbers *dependent* on earlier numbers. That is, you are deliberately picking something different or deliberately picking something the same. The math is a little messier with *independent* numbers.)
 
In the UK there is a sub game of the main lottery where you can pick a "dream number" of 7 digits. It is exactly the same as the format that FFXI is using in game, except it is 5 digits.

It's called "Dream Number" and you can read more about it here:

http://www.lottery.co.uk/dream-number.asp

To win, it's as follows:

Winning the Game

The top prize in the Dream Number game is a cool £500,000. There are six prize levels below this, going all the way down to the minimum win of £2. And how exactly does a player win? By getting as many digits of the Dream Number selected in the order they appear on the ticket.

For instance, if your Dream Number is 5436780, you need the number 5 to be drawn first, the number 4 to be drawn second, the number 3 to be drawn third, and so on. The more digits selected in the right order, the more you will win, as follows:

First 1 digit of your Dream Number £2
First 2 digits of your Dream Number in order £10
First 3 digits of your Dream Number in order £100
First 4 digits of your Dream Number in order £500
First 5 digits of your Dream Number in order £5,000
First 6 digits of your Dream Number in order £50,000
All 7 digits of your Dream Number in order £500,000
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Of course, in FFXI, it's backwards in terms of the matching number to win, but the same principle applies. This can be played everyday and the number is drawn once everyday. However ...

Dream Number Information

Dream Number, billed as one of the "most exciting lottery games of modern times", was launched in the UK to replace the Lotto Extra game in mid July 2006 offering a jackpot of £500,000 and six tiers of smaller prizes. However, it has proven more of a 'big yawn' for players than a dream with the top prize only being won twice in the first year of operation.
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Just another note, this game can be played seperately from the main lottery drawing, OR, if you purchase a ticket for the normal lottery, a dream number is generated for you regardless. Adding the fact that (probably) over a million tickets are sold in the UK alone everyday with the highest sales on Saturdays and Wednesdays (for the main lottery game) and there are no consistent winners, I think, it's safe to say that Rank 1 prizes on FFXI will not likely exceed over 5 people.

NOTE: Haven't done any maths, just a guestimate of rounding down 5 million tickets, assuming 500000 active players with 10 tickets each to 5 digits, compared to millions of tickets per day for 7 numbers matching over a span of a year, no data for 2007-2008 yet which only drew 2 winners between 2006-2007.

Just a thought really. I know it can't be directly compared due to some differences, but probably just to give an idea. Although 5 million tickets to 5 matching numbers on a 1-time-occasion is more likely compared to yield some more winners compared to a few million tickets to matching 7 numbers on a daily basis. I guess it's to give us some sort of idea of the "odds" to this game.

I think SE planned this out really nicely otherwise. It nearly ensures that winners will be rare.
 
jamal said:
I've always wanted to buy someone's signed heart chocolate in bazaar for 99,999,999...now that opportunity might become reality.
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lol then toss said sentimental item
 
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